Question

two charges 5×10^-6C and 10×10^-6C are separated by a distance of 10cm in a medium of relative permittivity 8. the force between them is​

Answer 1

Acc. to Me

epsilom not(εο)*k=Epsilom(ε)

Here ε is =8

q1=5*10^-6 C

q2=10*10^-6 C

r=0.1m

Here

F=1*q1*q2/4πε*r^2

F=5*10^-6*10*-6/4πε *(0.1)²

Multiply and divide by εο and make

1/4πεο=9*10^9

solve

Then F= 45 εο

I hope it help