two charges 5 micro C and 10 micro coulomb are seperaed by a distance of 10cm in a medium of relative permittivity 8. the force between them is
Answers
Answered by
2
F=8*5*10^-6*10*10^-6/10*10^-2*10*10^-2
=400*10^-12/100*10^-4
=4*10^-8N
hope this helps u.
Mahijaan:
Sorry to say but it is wrong answer
Similar questions