two charges 50 micro coulomb and 100 micro coulomb placed at a distance of 0.06m apart find the field and potential at a point between teo charges and 0.02 m from 50 micro coulomb
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Answer:
Electric field are vector quantities in this case they are acting in opposite direction.
E due to A=
r2
kq
=
(0⋅3)
2
(9×10
9
)(50μC)
(
x
^
)
E due to B=
(0⋅3)
2
(9×10
9
)(100μC)
(−
x
^
)
∴Net E=
(0⋅3)
2
9×10
9
(50−100)×10
−6
x
^
E=5×10
6
(−
x
^
) V/m
solution
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