Physics, asked by prince121kashyap, 9 months ago

Two charges 5uc & -5 uc are
placed at points A & B , 5cm
apart. Depict an equipotential
surface of the system.​

Answers

Answered by ribhur2102
0

Answer:

Q1= 5uc =  5 × 10-⁶

Q2 = -5uc = - 5 × 10-⁶

Radius = 5cm =0.05m

E = 1\4π€ [Q1|x + Q2\(0.05-x)]

Q1\x = -Q2\(0.05-x)                                                          RADIUS = 6CM

                                                                                   .________________.

5× 10-⁶\x  =  -5× 10-⁶\(0.05-x)                                  5uc                               -5uc

x = 0.05- x

x= 0.05\2

x=0.025m

An equipotential surface is the plane on which total potential is zero.

It is at the midpoint of the line AB and perpendicular to it.

MEANS AT THE CENTRE OF LINE AT 0.025m AWAY FROM EACH EACH

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