Question

Two charges 8 microcoulomb and 2 microcoulomb are at a distance 2 cm apart. at what distance a charge 1 microcoulomb must be placed from 2 microcoulomb, so that it is in equilibrium

Answer 1

Answer:

Hello!

Two positive charges of 1 microcoulomb and 2 microcoulomb are placed at 1 m apart the value of electric field in Newton per full at the middle point of the line joining of the charges will be

Note: the electric field at the midpoint due to both charges act in opposite directions, then: d² => (d/2)²

1 μC ._______Q1> __ <Q2_________. 2 μC

______________ 1 m ______________

Solving:

[First Step] Conversion of μC (microCoulomb) into C (Coulomb)  

Then the two punctual or punctiform charges q1 and q2 will look like this:

[Second Step] We have the following data, to E1 :

We will apply the data to the electric field intensity formula, see:

* to Q1

---------------------

[Third Step] We have the following data, to E2 :

Note: the electric field at the midpoint due to both charges act in opposite directions, then: d² => (d/2)²

We will apply the data to the electric field intensity formula, see:

* to Q2

[Fourth Step] Therefore, the Net Electric Field will be:

________________________

Explanation: