two charges 9 and 3 are placed at a distance R the distance of the point where electric field intensity will be zero is
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3e…………….…(•)…………………………e|<– – x – – –>|<– – – (r - x) – –>|
Where (•) = The point where electric field is 0
Electric field due to 3e = Eelectric field due to ek(3e) / (x)² = k(e) / (r - x)²3/x² = 1/(r - x)²Square root on both the sides√3/x = 1 / (r - x)x = √3(r - x)x = r√3 - x√3x + x√3 = r√3x(1 + √3) = r√3x = r√3 / (1 + √3) <= This is distance from 3e charge
Distance of (•) from e charge is=> r - x=> r - r√3 / (1 + √3)=> r [1 - (√3 / (1 + √3))]=> r [(1 + √3 - √3)/(1 + √3)]=> r / (1 + √3)
∴ b) r ÷ (1 + √3) from e charge… is the correct optionI hope this one is correct.
Where (•) = The point where electric field is 0
Electric field due to 3e = Eelectric field due to ek(3e) / (x)² = k(e) / (r - x)²3/x² = 1/(r - x)²Square root on both the sides√3/x = 1 / (r - x)x = √3(r - x)x = r√3 - x√3x + x√3 = r√3x(1 + √3) = r√3x = r√3 / (1 + √3) <= This is distance from 3e charge
Distance of (•) from e charge is=> r - x=> r - r√3 / (1 + √3)=> r [1 - (√3 / (1 + √3))]=> r [(1 + √3 - √3)/(1 + √3)]=> r / (1 + √3)
∴ b) r ÷ (1 + √3) from e charge… is the correct optionI hope this one is correct.
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