Question

Two charges 9q and 25q are kept d distance apart . Where should 3rd charge plac4d so that 3rd charge is in equilibrium

Answer 1

Answer:

Explanation:

Two charge +9e and +1e are kept at a distance of 16cm from each other , Let a q charge is kept r distance from +9e in such a way that it remains in equilibrium.

Now, at equilibrium

Force act on q due to +9e = Force act on q due to +1e

K(+9e)q/r² = k(+1e)q/(16 - r)²

9/r² = 1/(16 - r)²

Taking square root both sides,

3/r = 1/(16 - r)

48 - 3r = r

48 = 4r

r = 12cm

Hence, a point charge q is kept 12cm from +9e

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