Two charges are kept at a certain distance apart. If one of the charge is doubled and the other charge is made 1/8 times. What will be the distance so as to exert the same force.?
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initially,
F= Kq1q2/r²
If one of the charge is doubled and the other charge is made 1/8 times.
As both the forces are equal
Kq1q2/r²= 2Kq1q2/8r'².
1/r²=1/4r'²
r'²=r²/4
r'=r/2
I hope this helps ( ╹▽╹ )
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