Question

Two charges are placed at a certaiin distance.if the magnitude of each charge is doubled,the force will be

Answer 1

Answer:

The force will be 4 the initial force.

Explanation:

This is simple.

F (initial)= (kq^2)/r^2

F (final) = (k*2q*2q)/r^2

=(4kq^2)/r^2

=4 F(initial)

Hence done.