Two charges are placed at a distance of 10 cm from each other with a force of 3×10^-6 N .What will happen when the charge becomes double and the distance remains same?2. when separation becomes 30 cm .
Answers
Explanation:
Type your question...
PHYSICS
Two particles having charges q
1
and q
2
when kept at a certain distance, exert force F on each other. If distance is reduced to half, force between them becomes :
December 26, 2019
avatar
Ribiyana Suryadevara
Share
Save
ANSWER
Answer is C.
Coulomb's law describes the magnitude of the electrostatic force between two electric charges. The Coulomb's law formula is given as follows.
The force between 2 charges q
1
and q
2
is given by the formula F=k
r
2
q
1
×q
2
.
Where, q
1
: Charge of object 1
q
2
: Charge of object 2
r: Distance between the two objects
F: Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction
k: Coulomb Constant.
In this case, the distance between 2 charges is halved. So the new force becomes F
new
=k
(
2
r
)
2
q
1
×q
2
=
r
2
4×k×q
1
×q
2
=4F.
Hence, the force between the charges becomes 4F.
hope it helps