Question

Two charges are repelled by a force of 2.0 N. If the distance between them triples, what is the force between the charges?​

Answer 1

Answer:

Force between them is 0.22N

Explanation:

We know, F= kq1q2/r^2

Given F = 2N

Let F' = kq1q2/(3r)^2

= kq1q2/9r^2

=F/9

= 2/9= 0.22 N

Answer 2

Given:

Force between two charges , F = 2N

To Find :

If the distance between them triples, what is the force between the charges.

solution:

Electrostatic force:

Electrostatic force is attractive or repulsive force between two electric charges. If both charges or of same nature then they repel each other and if the charges are of different nature then they attract each other and it is given by.

F = Kq₁q₂/r² ( k = columbus constatnt)

as we can see F is inversely proportional to r²

therefore F₁/F₂ = (r₂/r₁)²

                2/F₂ =(3r₁/r₁)²

                2/F₂ = 9

                F₂ = 2/9 N

Hence the force will be 2/9 units.