Question

two charges are seperated by a distance then find the intensity of electric field of mid way of two point charges​

Answer 1

Answer:

E = 4kQ/d^2

Explanation:

Lets consider Charges are q1 and q2

Q = q1 + q2

Distance is d and at midpoint between two charge is d/2

E1 = kq1/(d/2)^2

E1 = 4 kq1/d^2

Same for E2 = 4 kq2/d^2

Now for E = E1 + E2

E = 4kq1/d^2 + 4kq2/d^2

E = 4k (q1+q2)/d^2

E = 4kQ/d^2