two charges each of 1 microcoulomb but opposite in sign are 1 cm apart. calculate the electric field at a point 10 cm in the axial line of the dipole
Answers
Answered by
6
Answer:
F=9×10^9×(q1q2) ÷r^2=9×10^9×10^-12×10
Answered by
26
Answer:
Here, q= 1microC= 1/1000000C.
2a= 1cm= 0.001m ,r=10cm =0.01m
On the axial line of dipole,
E= 2pr/4π absilun not x(r²-a²)²
= 9 x 1000000000 x2 x1/1000000 x 0.001x0.01/ (0.01-0.25 x 0.0001)²
= 18/0.0001(1-0.0025)²
= 18 x 10000 N/C
Similar questions