Question

Two charges kept at a distance of 20cm in air, attract to each other with a force of 40 Newton. If both charges are placed in a medium of dielectric constant 20, at the same distance then both charges will attract with the force of
a)40 N
b)20 N
c)10 N
d)2 N
ANSWER THIS QUESTION ASAP PLEASE​

Answer 1

Answer:

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correct answer (d) 2 N

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Explanation:

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Answer 2

If both charges are placed in a medium of dielectric constant 20, at the same distance then both charges will attract with the force of b) 20 N.

The formula for electric force can be found out by Coulomb's law. The equation is given below:

$F=(\frac{1}_{4 \pi \epsilon_{0}}})(\frac{q_{1}q_{2}}{r_{2}} )$

$k$ = dielectric constant in the above equation.

Now, it is given that,

$r_{1}=r_{2}\\ Charges \:are\: same\\ \epsilon_{1}=\epsilon_{2}\\ k_{1}=1\:(for\: air)\\ k_{2}=20$

Therefore,

$\frac{F_{1}}{F_{2}} =\frac{k_{2}}{k_{1}} \\ F_{2}=\frac{1\times40}{20} =20 N$

Thus, the electric force will be 20 N.