Two charges of 10uc and -40uc are placed 12 cm apart find the position of the point where the electric field is zero
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Explanation:
when electric field is zero; from the formula --->
q/4π€r²= q/4π€r'²
9×10^9 ×10×10^-6/r² =9×10^9×40×10 ^-6/(0.12-r)²
10/r²=40/(0.12-r)²
0.0144+r²-0.24r/r²=4
r²-0.24r+0.0144=4r²
3r²+0.24r-0.0144=0
solve the quadratic equation to get the value of r
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