Two charges of 16µc and 9µc when placed in dielectric medium at distance of 3m apart, find force between them.
1 point
a) 0.32 N
b)3 N
c)0.144N
d)4N
Answers
Answer:
Two charges of 16µc and 9µc when placed in dielectric medium at distance of 3m apart, find force between them (c)0.144N
Explanation:
Charge on the first sphere, q₁=16µc
Charge on the second sphere, q₂=9µc
Distance between the spheres, r=3 m
F= KQ₁Q₂/R²
where K=1/4π∈=9×10⁹
F=9×10⁹×16×9×10⁻¹²/9=144×1⁻³ N
Answer:
The force between the two charges = 0.144 N
Explanation:
Force of attraction between two forces in a dielectric medium is given by the equation,
F = (1/4π∈₀) × ((q₁ q₂)/r²)
Where ∈₀ is the permittivity of free space
charge, q₁ = 16 μc = 16 × 10⁻⁶ c
charge, q₂ = 9 μc = 9 × 10⁻⁶ c
distance between the two charges, r = 3m
The constant of proportionality, 1/4π∈₀ = 8.98755 × 10⁹
∴ F = (8.98755 × 10⁹) × ((16 × 10⁻⁶ × 9 × 10⁻⁶)/3²)
F = 8.98755 × 10⁹ × 16 × 10⁻¹²
F = 143.8008 × 10⁻³
F = 0.144 N