Physics, asked by tanishar141, 10 months ago

Two charges of 16 microcoulomb and 9 microcoulomb are separated by a distance of 12m. Determine the magnitude of force experience by q1 due to q2 and also direction
the force.

Answers

Answered by juhisingh7543287
3

Answer:

F12 means force on q1 due to q2 ,, F12= k×q1×q2/r^2 ,, F12= 9×10^9×16×10^-6×9×10-6/12×12 and ans is 9×10-3 N r^21 in vector form

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