Question

Two charges of 1c and 4c are placed 0.5 m apart the ratio of the coulomb forces experienced by then charges is

Answer 1

Answer:

ANSWER

Given : Q

1

=1 C Q

2

=8 C F=180 N

The electrostatic force between the charges F=

r

2

kQ

1

Q

2

where k=9×10

9

∴ 180=

r

2

9×10

9

×1×8

⟹r=20,000 m =20 km

Answer 2

Given : Two charges of 1c and 4c are placed 0.5 m apart.

To find : The ratio of the coulomb force experienced by the charges.

solution : From Coulomb's law,

let Q₁ and Q₂ are charges seperated r apart. magnitude of force experienced by each of them is, |F₁₂| = |F₂₁| = KQ₁Q₂/r².

here it is clear that force experienced by each them is equal in magnitude but there are directed in opposite directions.

Therefore, the ratio of the coulomb forces experienced by the charges is 1 : 1.

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