Question

Two charges of +25nC and -25nC are placed 6m apart . Find the intensity of electric field at a point 4m from the centre of electric dipole.
1. On axial line
2. On equitorial line

Answer 1

Answer:

(i) 4.2 × (10)^10 N/c

(ii) 2.1 × (10)^10 N/c

Explanation:

Given that ,

The two charges of +25 nC and -25 nC are placed 6 m apart

We know that ,

The dipole field at an equitorial at distance r from the centre of dipole is given by

thus,

E = 2x 2.1x (10)^10

E=4.2x(10)^10 N/c

therefore dipole feild at axial point  and equitorial point  are 4.2A(10)^10 N/c and 2.1A(10)^10 N/c