Question

Two charges of 2C and 5 C are placed in air. If distance between the charges is 1mm, then find force experienced by each charge

Answer 1

Answer:

9.0 × 10¹⁶ N

Explanation:

Given :

Two charge let say q₁ = 2 C and q₂ = 5 C

Distance between them d = 1 mm = 1 × 10⁻³ m

We are asked to find Force :

We know :

F = k q₁ q₂ / d²  [ k = 9.0 × 10⁹ N m² C⁻² ]

Putting values here we get :

= > F = ( 9.0 × 10⁹ × 2 × 5 ) / ( 1 × 10⁻³ )² N

= >  F = ( 9.0 × 10¹⁰ ) / ( 1 × 10⁻³ )² N

= >  F = ( 9.0 × 10¹⁰ ) / ( 10⁻⁶ N

= > F = 9.0 × 10¹⁶ N

Hence we get required answer!