Question

Two charges of 4uC each are placed at the corners
A and B of an equilateral triangle of side length
0.2 m. The electrical potential at C is​

Answer 1

Answer:

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Answer 2

Explanation:

We know V =kq/r

∴ Voltage at C= k(4μc)/0.2 + k(4μ)/0.2

= 2×(9×10^9)×4×10^-6 / 0.2

= 36×D^4V