Question

Two charges of 5 coloumb and 10 coloumb are seprated by 2m distance the find the force acting between them​

Answer 1

Explanation:

q1*q2/r^2

= 5*10/2^2

=50/4

=12.5

Answer 2

Given

Two charges of 5 coulomb and 10 coulomb are separated by 2 m distance

To Find

The force acting between them​

Solution

We know that

$\rm \longrightarrow F=\dfrac{k \times q1 \times q2}{r^{2}}$

Here

• F = Force
• k = Coulomb constant
• q = Charge
• r = Distance

Units

• F = Newton (N)
• k = N m² / C²
• q = Coulomb (C)
• r = metre (m)

According to the question

We are asked to find the force acting between them​

Therefore

We must find "F"

Given that

Two charges of 5 coulomb and 10 coulomb are separated by 2 m distance

Hence

• q₁ = 5 C
• q₂ = 10 C
• r = 2 m

We know that

• k = 9 × 10⁹ N m² / C²

Substituting the values

We get

$\rm \longrightarrow F=\dfrac{9 \times10^{9} \times 5 \times 10}{2^{2}} \ N$

$\rm \longrightarrow F=\dfrac{9 \times10^{9} \times 50}{4} \ N$

$\rm \longrightarrow F=\dfrac{450 \times10^{9}}{4} \ N$

$\rm \longrightarrow F=112.5 \times 10^{9} \ N$

Therefore

The force acting between them​ = 112.5 × 10⁹ N