Physics, asked by mannysingh1843, 10 months ago

Two charges of + 5 microcoulomb and minus 5 microcoulomb are placed at points a b which are. 6 metres

Answers

Answered by kalirajan
0

F=q1•q2/r^2.k. here k=9×10^9

=5.(-5)/5^2.9×10^7

=10^7×9

=9×10^9N

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