Two charges of 5 uc and 3uc are seperated by a distance of lo cm in air. If the distance of seperation is reduced by 5 cm and the kept in water, whose dielectric Constant is 8.0. Find the new force between them.
Answers
Answer:: The dipole moment p = qd
= (6.0 × 10–6C) × (4.0 × 10–10m)
= 24 × 10–16Cm.
Since torque τ = pE sin θ, we can write
τ = (24 × 10–16cm)
× 3.0 × 102 NC–1) sin 30º
=
72
2 × 10–14 Nm
= 36 × 10–14 Nm
If a dipole is placed in a non-uniform electric field, the forces on the charges – q
and +q will be unequal. Such as electric field will not only tend to rotate but also
displace the dipole in the direction of the field.: The dipole moment p = qd
= (6.0 × 10–6C) × (4.0 × 10–10m)
= 24 × 10–16Cm.
Since torque τ = pE sin θ, we can write
τ = (24 × 10–16cm)
× 3.0 × 102 NC–1) sin 30º
=
72
2 × 10–14 Nm
= 36 × 10–14 Nm
If a dipole is placed in a non-uniform electric field, the forces on the charges – q
and +q will be unequal. Such as electric field will not only tend to rotate but also
displace the dipole in the direction of the field.
Explanation: you would have to times it to 10 to get your 36 Nm