Question

two charges of 6 microcoulomb and minus 2 microcoulomb are separated by a distance of 13 cm apart in air find the electrostatic force between the charges

Answer 1

Answer:

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Explanation:

i solved this question by using coloumb law

Answer 2

Answer:

Two charges of 6 micro-coulomb and minus 2 micro-coulomb are separated by a distance of 13 cm apart in the air the electrostatic force between the charges is 6.3N

Explanation:

• The electrostatic force between two charges $q_{1} ,q_{2}$ separated by a distance $d$ is given by the formula

       $F=K\frac{q_{1} q_{2} }{r^{2} }$

       where the constant $K=9*10^{9}$

From the question, we have

the charges are $q_{1} =6*10^{-6}C$    and $q_{2} =-2*10^{-6}C$

the separation between them $r=13cm=0.13m$

therefore the force is

$F=\frac{9*10^{9}*6*10^{-6}*2*10^{-6} }{0.13^{2} }$

⇒ $F=6.3N$