Question

Two charges of 90nC and –80nC are separated by a distance of 3mm.​

Answer 1

Answer:

Coulomb’s Law

F

=

k

F=k

|

q

1

q

2

|

r

2

.

|q1q2|r2.

Coulomb’s law calculates the magnitude of the force FF between two point charges,

q

1

q1 and

q

2

q2 , separated by a distance

r

r . In SI units, the constant

k

k is equal to

k

=

8.988

×

10

9

k=8.988×109

N

⋅

m

2

C

2

N⋅m2C2

≈

8.99

×

10

9

≈8.99×109

N

⋅

m

2

C

2

N⋅m2C2 .

The electrostatic force is a vector quantity and is expressed in units of newtons. The force is understood to be along the line joining the two charges. (See Figure 2.)