Question

Two charges of each 10 µC are placed at the corners of an equilateral triangle of

side 3 cm. what will be the field at the third corner​

Answer 1

Answer:

E(resultant) = 10 root 3 *10^7 N/C

Used Formula :

Electric field E=kq /r ²

where,

q=charge on point charge

r=distance between point and point charge

Units Conversion :

q1=q2=10 uC = 10* 10^-6

r1=r2=3 cm = 3*10^-2 m

Note :

Electric field E is a vector quantity (direction and magnitude dependent)

So, Resultant should be taken in vector method