Physics, asked by tanyakopra1646, 1 year ago

Two charges of equal magnitude and at a distance r exert a force F on each other .If the charges are halved and distance b/w them is doubled,then the new force acting on each charge is

Answers

Answered by amitansuparida202

0

Answer:

F = k q² / r²

F' = k q²/16r²

F' = F/16

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