Question

Two charges of equal magnitudes and at a distance of ‘r’ distance exerts a force ‘F’ on each

other. If the two charges are halved and the distance between them is doubled, then the new force

acting on each charge is –

(i) /8


(ii) /4


(iii) 4F (iv)

/16​

Answer 1

If the charges are halved and the distance between them is doubled the electric force becomes (1/16)th times that of initial force.

Explanation:

The force produced between two charges is given by :

R is the distance between charges

If charges are halved,

Distance is doubled,

R' = 2R

New electric force is given by :

So, if the charges are halved and the distance between them is doubled the electric force becomes (1/16)th times that of initial force. Hence, this is the required solution.

Answer 2

Answer:

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