Physics, asked by simran8219siya, 1 month ago

Two charges of equal magnitudes and at a distance of ‘r’ distance exerts a force ‘F’ on each

other. If the two charges are halved and the distance between them is doubled, then the new force

acting on each charge is –

(i) F/8


(ii)F/4
(iii)4F
(iv) F/16​

Answers

Answered by Anonymous
2

Answer:

D) F/16 the force becomes (1/16)th times that of initial force.

Similar questions