Two charges of equal magnitudes kept at a distance r exert a force F on each other.If the charges are halved and distance between them is doubled, then the new force acting on each charge is
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Answer: hey mate here's your answe
Explanation:If the charges are halved and the distance between them is doubled the electric force becomes (1/16)th times that of initial force. So, if the charges are halved and the distance between them is doubled the electric force becomes (1/16)th times that of initial force. Hence, this is the required solution.
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