Question

Two charges of magnitude -2Q and +Q are located points (a,0) and (4a,0) respectively what is the electric flux due to these charges through a sphere of radius '3a' with it's centre at the origin​

Answer 1

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Answer 2

Using Gauss's law

Flux(ϕ)= q/ϵ0

where, q is the total charge inside the surface

Here, q=−2Q and gaussian surface is a sphere of radius 3a and center at origin.

So,Flux(ϕ)= -2Q/ϵ0

Here, flux is only due to charge -2Q because no. of field lines enter the sphere due to charge +Q is equal to no. of field lines coming out of the sphere, so net flux is zero due to charge +Q.