two charges of magnitude 5nC and -2nC are placed at points (2,0,0) and (x,0,0) in a region of space where there is no external field . If electrostatic potential of the system is -0.5 j ,find the value of x
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Explanation:
For a square ABCD, OA=OB=OC=OD=r
As charge 5μC is placed on center O so every point A,B,C and D have same potential V=5k/r.
Thus potential difference (dV) between A and B will be zero.
Work done W=qdV=1(0)=0
solution
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