Two charges of magnitudes 1c and 3c are placed 3m apart. find the magnitude of electric force acting between them.
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Magnitude of first charge = q1 = 1 C
Magnitude of second charge = q2 = 3 C
Distance between the two charges = 3 m
The force acting between two charges is found using Coulomb's law.
According to Coulomb's law,
Force between two charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them.
Therefore, F = (k × q1 × q2)/ r²
where, k is a constant of proportionality
The value of k depends on medium.
In vacuum/air, the value of k is 9 × 10^9 N m²/C².
Since, the medium is not given in the question, we will assume that the charges are in vacuum/air.
Therefore, from above equation, we get
F = (9 × 10^9 × 1 × 3)/ 3²
=> F = 3 × 10^9 N. (Ans)
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