Question

two charges, one of which is twice the other repel each other with a force equal to the wgt of 72 mg wgt. When the changes are 10cm apart, find their magnitude when kept in a)air b)glass with k=6

Answer 1

Answer:a.2×10^-4 b.

Explanation:

Answer 2

Hello there,

The question doesn't seem to be complete, and the information is not conveyed properly... but anyways ... you can solve the actual question after understanding the concept .

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I guess uk Coulomb's law?.... K....

so... there this relationship and a concept behind this relationship formulated by this guy (# who is ded now) ...but his contributions to science and physics were quite significant.

So...

Coulomb's law... explained:

'The mutual force of attraction between two chargers is proportional to the product of the magnitude of the two charges and is inverse proportional to the square of the distance between them'

....

Mathematically.....

[F = $\frac{1}{4 \pi \epsilon} \frac{q_{1} . q_{2} }{r^{2} }$]

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given

$q_{1}$ = 2 $q_{2}$

r = 10 cm , i.e 10 x $10^{-2}$ m

and F =72 mg wgt  =72 x $10^{-2}$ N

varying ∈ for air and glass we can find the magnitude of the two charges.

take ratio of forces and find result.....

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cheers.