Question

two charges Q and 4Q are 12 cm apart calcuted the distance of neutral point from 4Q charge ​

Answer 1

The neutral point at distance 8 cm from 4Q charge.

Explanation:

Given that,

First charge = Q

Second charge = 4Q

Distance = 12 cm

Let the neutral point at distance x from 4Q charge.

At this point the electric field due to both charges will be same

We need to calculate the distance

Using formula of electric field

$\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{Q_{2}}{x^2}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{Q_{1}}{(d-x)^2}$

Put the value into the formula

$\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{4Q}{x^2}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{Q}{(12-x)^2}$

$\dfrac{4}{x^2}=\dfrac{1}{(12-x)^2}$

$24-2x=x$

$3x=24$

$x=8\ cm$

Hence, The neutral point at distance 8 cm from 4Q charge.

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Topic : electric field

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