Question

two charges- q and + q ÷ 2 are situated at the origin and at the point (a,0,0) respectively the point along the x axis where the electric field vanished is​

Answer 1

Explanation:

let the electric field be zero at a position x from the origin

1= particle +q

2=particle -2q

we know that electric field can be zero only at one place ie on the left of particle +q

E1=kq/(a-x)²

E2-k(-2q)/(2a-x)²

E1+E2=0

E1=-E2

kq/(a-x)²=2qk/(2a-x)²

1/a-x= √2/(2a-x)

2a-x=√2(a-x)

2a-√2a -√2x+x

√2a(√2-1)=-x(√2-1)

x=-√2a

therefore its at a distance of √2a on the left side of number line.