Question

Two charges q₁ and q₂ are at a distance 2m, where q₁=8μC and q₂=10μC .What is the force between the charges?

Answer 1

Given,
distance(r)=2m
q1=8*10^-6 C
q2=10*10^-6 C
force between them(F)=?
we know that,by Coulomb's law;
F=k(q1*q2)/(r^2) [where k=9*10^9 Nm^2/C^2 appr.]
F=9*10^9[8*10*10^(-6-6)]/2^2
F=18*10^-2
F=0.18 N
therefore,force between given two charges is 0.18 N

Answer 2

Sub in Coulomb's law 1/4piepsilonnot product of charges /distance square
on further solving 180 *10 power -2
 newton