two charges Q1 and Q2 are placed in air at distance 30cm then find the distance in medium of dielectric constant 9.such that force between the charges remain same?
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Answer:
when dielectric is added ε
0
becomes kε
0
where k is dielectric constant
we known F
i
=
4π ε
0
1
r
2
Q
1
Q
2
when dielectric is added f
f
=
4π kε
0
1
r
2
Q
1
Q
2
∴F
f
=
2
5
=2⋅5 units
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