Two charges q1 and q2 are placed in vacuum at a distance d and force between
them is F. If a medium of relative permittivity 4 is introduced between them, then
the new force will be
A. F/4
B. F/2
C. 2F
D. 4F
Answers
Answered by
57
Answer:
F/4
Explanation:
The electrostatic force between two charge q1 and q2 separated at distance d is
If a medium of relativity in introduced then the electrostatic force is
= F/e = F/4
Answered by
9
Answer:
answer of this question is F/4
Similar questions
Science,
5 months ago
Social Sciences,
5 months ago
Computer Science,
5 months ago
Math,
10 months ago
History,
10 months ago
India Languages,
1 year ago