Physics, asked by starmogh297, 11 months ago

Two charges q1 and q2 placed at a separation d in air experience a force of 12n. If the separation is changed,the force becomes 3n. What is the value of new sepation in terms of d

Answers

Answered by rajrobin30
3

Answer:

Look at ans...above..........

Attachments:
Answered by alexaura
0

Answer:

d' = 2d

Explanation:

F = (kq1q2)/(d^2) = 12 N

F' = (kq1q2)/(d')^2 = 3 N

F/F' = d'/d = 2

      = d' = 2d

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