Question

Two charges q1 and q2 placed at a separation d in air experience a force of 12n. If the separation is changed,the force becomes 3n. What is the value of new sepation in terms of d

Answer 1

Answer:

Look at ans...above..........

Answer 2

Answer:

d' = 2d

Explanation:

F = (kq1q2)/(d^2) = 12 N

F' = (kq1q2)/(d')^2 = 3 N

F/F' = d'/d = 2

      = d' = 2d