Two charges q1 and q2 placed at a separation d in air experience a force of 12n. If the separation is changed,the force becomes 3n. What is the value of new sepation in terms of d
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Answer:
d' = 2d
Explanation:
F = (kq1q2)/(d^2) = 12 N
F' = (kq1q2)/(d')^2 = 3 N
F/F' = d'/d = 2
= d' = 2d
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