Question

Two charges when kept at a distance of 1m
apart in vacuum have some force of
repulsion. If the force of repulsion between
these two charges be same, when placed
in an oil of dielectric constant 4, the
distance of separation is​

Answer 1

Answer:

Correct option is

C

0.5m

In vacuum force of repulsion =

4πε

0

1

(1)

2

q

1

q

2

given the force of repulsion is same in oil so let the distance in oil be X.

⇒

4πε

0

1

(1)

2

q

1

q

2

=

4πKε

0

1

X

2

q

1

q

2

⇒

1

K

=

X

2

1

⇒4=

X

2

1

⇒2=

X

1

⇒X=0.5m