Question

Two children differ in their age by 2 years. Six years later, the sum of their ages will be 46. How old are they now?​

Answer 1

:

your question is worng.

Step-by-step explanation:

If ,first child's age be x

second child's be x+2

now, after 6years their sum of the age is 46.

so, x+x+2+6 = 46

2x+2+6=46

2(x+1)+6=46

2(x+1)=46-6

2(x+1) =40

x+1=40/2

x+1=20

x=19

Answer 2

Step-by-step explanation:

let the child 1 be x

child 2 will be x+2

after 6 years,

child 1 = x+6

child 2 = (x+2)+6

= x+8

according to the question,

x+6 + x+8 =46

2x + 14 = 46

2x = 46-14

2x = 32

x= 16

child 1 = x = 16

child 2 = x+2 =18

ans. child 1 is 16 year old and child 2 is 18