two children of same weight start climbing a rope where A takes 20sec and B takes 15 sec to accomplish the task what is work done by each
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Answer:A B
m=32 kg m=32kg
common height=8 m
t=15 secs t=20 secs
therefore, work done by A n B will be same = FS = maS
= 32 * 10 *8
= 2560 J
Power of A = W/t = 2560/15 = 170.7watt
Power of B = 2560/20 = 128 watt
hence A has more power comparable to B
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