Two chimney 16m and 13m high stand upright in a ground .If their feet 4m apart then find the distance between their tops.
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at the top of 13m chimney the perpendicular distance will still be 4m and on 16m chimney only 3m of top will be left from 13m perpendicular level
so a right angled triangle is formed with base = 4m and height = 3m ..just visualize it yourself
then hypotenuse = distance between the tops
so h^2 = perpendicualr^2 + base^2
h^2 = 3^2 + 14^2
h^2 = 9+16
h^2 = 25
h = 25 ^ 1/2
h = 5m
so the distance between the tops of chimneys is 5m
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