Question

Two chords AB and BC are perpendicular to each other of a circle of radius 5 then what is the length of AC

Answer 1

Answer:

We know that, if AB and AC are two equal chords of a circle, then the centre of the circle lies on the bisector of  

∠BAC.

Here, AB=AC=6cm. So, the bisecor of ∠BAC passes through the centre O i.e. OA is the bisector of ∠BAC.

Since, the internal bisector of an angle divides the opposite sides in the ratio of the sides containing the  

angle. Therefore, M divides BC in the ratio 1:1, i.e. M is the mid-point of BC.