Two chords AB and CD of a circke intersect at an external point P,as shown in the figure.If AB=8cm,BP=10cm,PD=12cm Find
a)PC
b) area(triangleBPD)/area(triangleAPC)
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Ans. a) PC = 15cm
b) area (triangle BPD) /area( triangleAPC) = 4/9
solution is in the pic ...
b) area (triangle BPD) /area( triangleAPC) = 4/9
solution is in the pic ...
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