Question

Two chords AB and CD of a circle interest each other at the point P(when produced) outside the circle. Prove that
triangle PAC is similar to triangle PDB.​

Answer 1

Answer:

hope this is the correct answer bro.........

Answer 2

Answer:

Ans. (i) In the triangles PAC and PDB,

APC = DPB [Common]

CAP = BDP [BAC = PAC and PDB = CDB]

= BAC = = PAC]

By AA-criterion of similarity,

APC DPB

(ii) Since APC DPB

PA.PB = PC.PD