Question

Two chords AB and CD of a circle intersect each other
at a point E outside the circle. If AB = 11 cm, BE = 3
cm, and DE = 3.5 cm, then CD = ?​

Answer 1

Answer:

CD=3.9cm

Step-by-step explanation:

We are given two chords AB and CD of a circle intersect each other at P outside the circle.

We have a formula if two chord intersect each other

AP\times BP=CP\times DPAP×BP=CP×DP

where, AB=6 cm, BP=2 cm and PD=2.5 CM

AP=AB+BP

AP=6+2 = 8 cm

Substitute into formula and we get

\begin{gathered}8\times 2=CP\times 2.5\\16=2.5CP\\CP=6.4\end{gathered}

8×2=CP×2.5

16=2.5CP

CP=6.4

cm

CP=CD+DP

6.4=CD+2.5

CD=3.9 cm

Answer 2

Step-by-step explanation:

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