Question

Two chords AB and CD of a circle intersect each other at P outside the circle. If AB= 5 cm, BP= 3 cm and PD = 2 cm, find CD.

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Here the chords AB and CD intersect each other at P outside the circle.

PA×PB=PC×PD

10×PB=6×5

PB=

10

30

=3cm

Step-by-step explanation:

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